woh !!!!!!! it's high power

Number Theory Level 3

Let k= (2012)^2 + 2^2012 , then last two digit of the equation is


The answer is 40.

Tejashv Chaturvedi by Tejashv chaturvedi , 23, India

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2 solutions

Yoko Setiawan
Jul 24, 2014

(2012)^2= we just only need 12^2=144, then 2^2012= we just only need 2^12=4096, so 144+4096=4240, then for the last 2 digit is 40

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I mess up with 2012

Gonna Sing - 6 years, 10 months ago

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I too did the same

vishwesh agrawal - 6 years, 2 months ago
Adnan Galib
May 4, 2014

〖2012〗^2=4048144 For 2^2012= (2^2000 x 2^12),consider only 2^12=4096,because the 2^12 will regulate the power So, 4048144+4096= 4052240, The last digit will be = 40

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