Factoring...

Algebra Level 2

We are given the system of equation in real numbers x , y x,y :

{ x y + x + y + 7 = 0 3 x + 3 y = 9 + 2 x y \begin{cases} xy+x+y+7=0\\ 3x+3y=9+2xy\\ \end{cases}

Determine x 2 y + x y 2 x^2y+xy^2 .


The answer is 6.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Aquilino Madeira
May 14, 2016

{ x y + x + y + 7 = 0 3 x + 3 y = 9 + 2 x y { x + y = x y 7 3 ( x + y ) = 9 + 2 x y { x + y = x y 7 3 ( x y 7 ) = 9 + 2 x y { x + y = x y 7 3 x y 21 = 9 + 2 x y { x + y = x y 7 5 x y = 30 { x + y = x y 7 x y = 6 { x + y = ( 6 ) 7 x y = 6 { x + y = 1 x y = 6 x 2 y + x y 2 = x y ( x + y ) = 6 ( 1 ) = 6 \begin{array}{l} \left\{ \begin{array}{l} xy + x + y + 7 = 0\\ 3x + 3y = 9 + 2xy \end{array} \right. \Leftrightarrow \left\{ \begin{array}{l} x + y = - xy - 7\\ 3\left( {x + y} \right) = 9 + 2xy \end{array} \right. \Leftrightarrow \left\{ \begin{array}{l} x + y = - xy - 7\\ 3\left( { - xy - 7} \right) = 9 + 2xy \end{array} \right.\\ \left\{ \begin{array}{l} x + y = - xy - 7\\ - 3xy - 21 = 9 + 2xy \end{array} \right. \Leftrightarrow \left\{ \begin{array}{l} x + y = - xy - 7\\ - 5xy = 30 \end{array} \right. \Leftrightarrow \left\{ \begin{array}{l} x + y = - xy - 7\\ xy = - 6 \end{array} \right.\\ \left\{ \begin{array}{l} x + y = - ( - 6) - 7\\ xy = - 6 \end{array} \right. \Leftrightarrow \left\{ \begin{array}{l} x + y = - 1\\ xy = - 6 \end{array} \right.\\ \\ {x^2}y + x{y^2} = xy\left( {x + y} \right) = - 6( - 1) = 6 \end{array}

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...