Woodcutters!

Logic Level 2

Three teams of woodcutters take part in a competition.The first and the third teams put together produced twice the amount cut by the second team.The second and the third team put together yielded a three-folded output as compared with the first team. Which of the teams won the competition?

First team There is a tie Second team Cannot be determined Third team

Naitik Sanghavi by naitik sanghavi , 20, India

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2 solutions

Jhon Galegru
Aug 7, 2015

Let amount cut by the first, second and third team be x, y and z respectively. x+z=2y (1) y+z=3x (2) Subtracting eq. (2) from (1) x-y=2y-3x => 4x=3y (3) => y=(4/3) x Using eq. (3) and (1) x+z=(8/3) x => z=(5/3)*x Hence, z>y>x

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Take first team as a a , second team as b b and third team as c c Take one fold as x x

a + c = 2 x a + c = 2x

b + c = 3 x b + c = 3x

a + c − c − b = − x a + c - c - b = -x

b + c − c − a = x b + c - c - a = x

b b is bigger than a a

If b > a b > a and a + c < b + c a + c < b + c and b − a = x b - a = x

And if a + c = 2 x a + c = 2x and b + c = 3 x b + c = 3x

Then, c > b > a c > b > a

0 Helpful 0 Interesting 0 Brilliant 0 Confused

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