Word Game

Level pending

In this game of mine, there are three words - " Ram , Shyam and Ghanshyam ", Let the number of ways can you arrange the letters of word "Ram" distinctly be denoted by 'a' .Similarly, let the number of ways can you arrange the word "Shyam" distinctly be denoted by ' b'.

So,,,,,,What is the square root of (a x b x 5) ?


The answer is 60.

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2 solutions

Ayushi Goel
Dec 12, 2014

you can arrange the 'n' letters of any word in n! ways. therefore letters of ram can b arranged in 3! ways n dat of shyam in 5! ways. thus a b 5=3600 and square root of dis is 60.

You can arrange the 3 letters in Ram 3! ways or 3 × \times 2 × \times 1 or 6 \boxed{6} ways. You can arrange the 5 letters in Shyam 5! ways, or 5 × \times 4 × \times 3 × \times 2 × \times 1 or 120 \boxed{120} ways. 6 × \times 120 × \times 5 = 3600 \boxed{3600} . 3600 \sqrt{3600} = 60 \boxed{60} .

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