Word Logic - 4
NOTE - There are more questions based on the passage below. Check all the questions on my profile page.
A linguist wants to make a word out of the following nine letters: A,B,C,D,E,F,G,H,I
The word must have atleast three letters. Each letter can be used only once.
Following conditions must also be satisfied:
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If H is selected, atleast 5 others must be selected
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If G is selected, atmost 3 others must be selected
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If C or D is selected, G is selected
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Vowels can not be next to each other
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Atleast two out of the 3 vowels must be selected
Which of the following is a complete and accurate list of the letters, any one of which could be the 2nd letter of the shortest possible word?
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1 solution
Choosing H will give us 6-letter words. Choosing C or D will give us at least 4-letter words. Choosing B, F and G each and separately won't make us add on unnecessary letters other than the conditioned vowels, for which 2 of them is mandatory but cannot be adjacent. There are 18 shortest words in all.
ABE, ABI, EBA, EBI, IBA, IBE, AFE, AFI, EFA, EFI, IFA, IFE, AGE, AGI, EGA, EGI, IGA and IGE.