Work done by the electric field

A bumble bee charged to 1 C 1 \text{ C} flies from ( 0 m , 0 m ) (0 \text{ m}, 0\text{ m}) to ( 1 m , 1 m ) (1 \text{ m}, 1\text{ m}) through a region with electric field E = ( x ^ + y ^ ) N C \vec{E}=(\hat{x}+\hat{y})\dfrac{N}{C} . Find the work done by the electric field on the bumble bee.

1 J 1 \text{ J} 2 J \sqrt2 \text{ J} 2 J 2 \text{ J} 2 2 J 2\sqrt2 \text{ J}

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2 solutions

July Thomas
Apr 6, 2016

Relevant wiki: Conservative nature of Electric fields

The work done is W = q E d W=qEd_{\parallel} . Since the electric field is conservative, any path from (0,0) to (1,1) can be used. The quickest path goes (0, 0) -> (1, 0) ->(1, 1)

Isn't the quickest path is a straight line from (0,0) to (1,1) witch length is sqrt2?

Вячеслав Чаунин - 1 year, 2 months ago
Debanksh Mohanty
Aug 20, 2017

w=q E d= 1C sqrt2 sqrt2=2

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