A mono-atomic gas undergoes a process in which it uses 50% of heat in work done by gas. If the process equation of gas is V P k = constant then value of ' k ' will be
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5 0 % of heat is used up as work done by gas. ⇒ 5 0 % of heat is used in increasing the internal energy of the gas.
⇒ Δ U = 2 1 Δ Q
Δ U = n C v Δ T = n γ − 1 R Δ T and Δ Q = n C Δ T , C = γ − 1 R + 1 − x R where x is polytropic factor.
n γ − 1 R Δ T = 2 1 × n ( γ − 1 R + 1 − x R ) Δ T
γ − 1 R = 1 − x R
γ − 1 = 1 − x
x = 2 − γ = 2 − 3 5 = 3 1
The process is P V x = k and x = 3 1 ⇒ P 3 V = k 3 = c o n s t .
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For a process P V x = c o n s t a n t
molar specific heat capacity C = γ − 1 R + 1 − x R
W = 1 − x n R d T
where γ is ratio of specific heat capacities
H = n C d T and here x = k 1 and γ = 3 5
Given in the question 2 H = W
on solving
k − 1 k = 2 3
k = 3