Sufficient work done?

A smooth track in the form of a quarter circle of radius 6 m 6\text{ m} lies in the vertical plaine (as shown in figure above). A particle of weight 4 N 4N moves from P 1 P_1 to P 2 P_2 under the action of forces F 1 , F 2 , F 3 \vec{F_1}, \vec{F_2}, \vec{F_3} . Force F 1 \vec{F_1} is always towards P 2 P_2 and is always 20 N 20N in magnitude, force F 2 \vec{F_2} always acts horizontally and is always 30 N 30N in magnitude, force F 3 \vec{F_3} always acts tangentially to the track and is of magnitude ( 15 10 s ) N (15-10s)N when s s is in meters.

If the particle has speed 4 m/s 4 \text{ m/s} at P 1 P_1 , what will be its speed be at P 2 P_2 ? Give your answer in 1 decimal place and in m/s \text{ m/s} . Assume take g = 9.8 m/s 2 g = 9.8 \text{ m/s}^2 .


The answer is 11.3.

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1 solution

Rahul Badenkal
Jun 20, 2015

Thanks you are awesome

Ndkdlsls Ndkssksndjdj - 4 years, 1 month ago

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Bhai dhassu

Chuppa Chuppa - 3 years, 5 months ago

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