Work Problems - Easy 2

Algebra Level 2

Kiosk A can sell a certain amount of burgers in 12 12 hours, and Kiosk B can sell the same amount of burgers in 18 18 hours. If Kiosk B works together with Kiosk A after Kiosk A completes half of the job, how many hours will they finish selling all the burgers?

Note

  • Exact answer is up to 1 decimal place only


The answer is 9.6.

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1 solution

Jeremy Bansil
Nov 22, 2014

Kiosk A completed half of the job before Kiosk B joined Kiosk A. So half of 12 12 hours is 6 6 hours.

However, we can use the same equation on the previous problem to get the combined work of both kiosks.

x y x + y \frac {xy}{x+y} = number of total hours if worked together \text{number of total hours if worked together}

( 12 ) ( 18 ) 12 + 18 = 216 30 = 7.2 \frac {(12)(18)}{12+18} = \frac {216}{30} = 7.2

Since half of the work is already done, divide 7.2 7.2 by 2 2 . You will get 3.6 3.6 .

Now they will complete their job in 6 + 3.6 = 9.6 6 + 3.6 = \boxed{9.6} hours.

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