Work, work and work!!!

The speed of $X$ is $\frac{1}{12} \frac{\text{work}}{\text{day}}$ and the speed of $Y$ is $\frac{1}{24} \frac{\text{work}}{\text{day}}$ . Together, their speed becomes $\frac{1}{12} + \frac{1}{24} = \frac{1}{8 }\frac{\text{work}}{\text{day}}$ .

It is very clear that they will complete $1$ work after $8$ days now.

to solve this question we must know how many work that was done by each worker in one day

if, in 12 days xeno completes a work. in 1 day xeno complete $12 days = 1 work$ $1 days = \frac{1}{12} work$ if, in 24 days yahle completes a work, in 1 day yahle complete $24 days = 1 work$ $1 days = \frac{1}{24} work$ because yahle and xena work together, so in 1 day both of them complete $1 days = \frac{1}{12} work + \frac{1}{24} work$ $1 days = \frac{1}{8} work$ if, in 1 days both of them complete 1/8 work. in 8 days they can complete $8 days = \frac{1}{8} work \times 8$ $8 days = 1 work$ therefore, in 8 days both of them can complete 1 work

Xeno completes a work in 12 days, which means in one day he completes $\frac{1}{12}$ th of the work.

In $x$ days, Xeno will complete $\frac{1}{12} \times x$ of the work.

Yahle completes the same work in 24 days, which means in one day she completes $\frac{1}{24}$ th of the work.

In $x$ days, Yahle will complete $\frac{1}{24} \times x$ of the work.

If both of them work together and if they complete the work in $x$ days, then

$\frac{1}{12} \times x + \frac{1}{24} \times x = 1$

$\frac{x}{12} + \frac{x}{24} = 1$

$\frac{2x + x}{24} = 1$

$\frac{3x}{24} = 1$

$3x = 24$

$x = 8$

That's the answer!

Let x=12 y=24

Then y=2x

y+x=2x+x=12 3x=12 x=4

12-4=8

In 1 day, Xeno completes 1/12 of work, Yahle completes 1/24 of work, and both of them will completes 1/12 + 1/24 = 1/8 of work. So, they completes the work in 8 days.

Let the total units of work to be done be 24. (We decide on 24 since it is the LCM of 12 and 24).

Xeno will do 2 units of work per day. Yahle will do 1 unit of work per day.

Total Work done per day = 3 units. Hence, no of days required = 24/3 = 8 days.

We can also get the answer as the reciprocal of 1/12 + 1/24, which is again 8.

Xeno has a rate of work which is double Yahle,s Work,so to make it easier lets assume that xeno and yahle has a work of making 30 T-shirts both: so Xeno will make 30 shirts in 12 days so his speed of making shirts is 2.5 shirts /day Yahle in the other hand will make 30 shirts in 24 days so his speed of making shirts must be 1.25 shirt / day Summing up Yahle and Xeno speed per day will give us the speed of making shirts per day which will be 3.75 shirt/ day Dividing the number of shirts which is 30 shirts by 3.75 (speed) will give us the number of days needed

(1/24) + (1/12) = 1/8. so, they can finish the work about 8 days.

xeno=12days yhale=24days

zeno+yhale=??

xeno = 1/12 yhale= 1/24

C=x+y

1/12 + 1/24

2/24 + 1/24

3/24 invert = 24/3 = {8}

(1/12)+(1/24)=1/x, then 1/x=3/24, then answer x=8

Time taken to complete work = Bigger No/Sum of Ratios. Therefore, Bigger No is 24. 24/(12:24) = 1:2 Hence. No. of days = 24/(1+2) = 24/3 = 8 Days

Let's say that the work is painting 12 bricks. Xeno can paint at the rate of 1 brick per day. Yahle can paint $\frac{1}{2}$ a brick per day. After the first day of working together they will have painted $\frac{3}{2}$ bricks. To find how many days they would need to complete the work one divides the number of bricks by the daily rate.

12 bricks at $\frac{3}{2}$ per day will be 8 days.

In a day, Xeno would do 1/12 of his work; Yahle would finish 1/24 of his work. If they worked together, they'd do 1/12 + 1/24 = 1/8 of the work a day. So, it would take them 8 days to complete the work.

My idea of solving this problem is just dividing 100% of the work by the days Xeno worked and that give me 8.33% per day. Then, Yahle worked 100% / 24 days and give me 4.16% of work per day. If we add this quantities, gives 12.49% per day. Then 100% divided by 12.49 gives us 8.0...something. And we can assume that, Xeno and Yahle working together, will finish the work in 8 days.

let x = the amount of days that the two people to work together, so that

$\frac{x}{12}+\frac{x}{24}=1$

$\frac{2x+x}{24}=1$

$3x=24$

$x=8$

Since it takes Xeno to complete a work in 12 days, then every day he completes 1/12 or 2/24 the work.. And since it takes Yahle to complete the work in 24 days . Each days she completes 1/24 the work. If we add them both together, each day they complete 3/24 the work. Now using the recipricol of the fraction 24/3 , the answer is 8

Xeno does total work in 12 days and Yahle does total work in 24 days.

So, in 1 day, Xeno does $\frac{1}{12}$ part and Yahle does $\frac{1}{24}$ part of the work.

Both do ( $\frac{1}{12}$ + $\frac{1}{24}$ ) = $\frac{(2+1)}{24}$ = $\frac{3}{24}$ = $\frac{1}{8}$ part of work in one day together.

So, they do total work in = $\frac{1}{1/8}$ = $\boxed{8}$ days.

let P be work p1 be the work rate of Xeno and p2 be the work rate of Yahle P=p1 12 P=p2 24 so p1 & p2 are P/12 and P/24 resp.| now, time= work / work rate work rate together= p1+p2 time = P/ (P/8) =8

In 1 day, Xeno would have done 1/12 of the work, and Yahle would have done 1/24 of the work.

So, if they work together, they would accomplish (1/12+1/24=1/8) of the work in 1 day.

Thus 8 days are required to complete the work if they work together.

Both do 1/8 work in a day so 8 is the answer.

1/12+1/24=3/24 reciprocal due to time and work because with respect of time we do work so we reciprocal it as a 24/3

x complete work in 1/12 days. work/day. y complete work in 1/24 days. work/day. if both work together 1/12+1/24=3/24.
=1/8.
with in 8 days both can complete work.

When they work together, total work can be done together= 3/24=1/8. We then formulate the equation (1/12+1/24)x= 1 . Solving x, we get the number of days required i.e= 8

Work done by Xeno in 1 day= $\frac {1}{12}$ . Work done by Yahle in 1 day= $\frac {1}{24}$ . Therefore,work done by both in 1 day= $\frac {1}{12}$ + $\frac {1}{24}$ = $\frac {1}{8}$ . Therefore,time taken by both of them together to finish work = 8 days.

Y works at half the pace of X,

X+Y works at 1.5 times the pace of X

X takes 12 days,

Y+X=12/1.5

=8days

coz they has 1:2 in regards to time consumption

Let us divide the total work into pieces. that is UNIT WORKS since xenon completes Total work in 12 days, so let us divide total work into 12 UNITS OF WORK xenon ------------1Day-------------1Unit of work (UW) Yahle-------------2Days-----------1Unit of work it means he completes 0.5 Unit of work in one day if both together works for one day they will complete 1.5 units of work Total UNITS OF WORKS = 12 (work of xenon and yahle)X(no of days) = Total UNITS OF WORK 1.5*Days=12 Days=8 ANS = 8 DAYS

Find the work rate of both. It can be shown as $\frac{1}{x} \text{ work done per day.}$ $\text{Xeno: } \frac{1}{12}$

$\text{Yahle: } \frac{1}{24}$

When you add the two work rates together, you will get the work rate of both of them working at the same time.

$\frac{1}{12} + \frac{1}{24} = \frac{1}{x}$

Where x is the days where both are working.

Solve.

$\frac{2}{24} + \frac{1}{24} = \frac{1}{x}$

$\frac{3}{24} = \frac{1}{x}$

$3x = 24$

$x = 8$

So the days that both are working together are $\boxed{8 \text{ days.}}$

Xeno completes one work in 12 days, so 1work/12 days. Yahle completes the same work in 24 days, so 1 work/12 days. if they both work together you add the two fractions. 1/12 + 1/24 = 3/24 = 8.

By using rates, 1/12+ 1/24=1/x That gives us: 1/8=1/x so x=8

1/12 + 1/24 = 1/8 AMOUNT OF WORK IN 1 DAY SO , 8 DAYS TO COMPLETE 1 WORK TOGETHER