Working out the work

The switch S is kept in position 1 till steady state is reached.then it is transferred to position 2. The charge on the 3F capacitor on transferring switch from 1 to 2 is QC .the work done by the battery is WJ . Calculate the value of. 38 Q + 5 W 17 \frac{38Q+5W}{17}


The answer is 1000.

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