World War 1

Algebra Level 4

During the World War 1, the Germans suffered heavy casualties.
65% of the tanks lost their guns,
75% lost their commander, and
85% lost their track.

If every tank lost at least one of the commander, the gun, or the track, and 15% lost exactly one of these, how many lost all three?

10% 20% 30% 40%

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Let a, b, c, d, e, f, and g as follows:

Thus,

(1) a + d + f + g = 65 a + d + f + g = 65 [65% of the tanks lost their guns]

(2) b + e + f + g = 75 b + e + f + g = 75 [75% lost their commander]

(3) c + d + e + g = 85 c +d + e + g = 85 [85% lost their track]

(4) a + b + c = 15 a + b + c = 15 [15% lost exactly one]

(5) a + b + c + d + e + f + g = 100 a + b + c + d + e + f + g = 100 [total]

Adding the equations (1), (2), and (3) yields:

(6) a + b + c + 2 d + 2 e + 2 f + 3 g = 225. a + b + c + 2d + 2e + 2f + 3g =225.

Subtracting equation (5) in from equation (6) yields

(7) d + e + f + g = 125. d + e + f + g = 125.

Substituting equation (4) in equation (6) yields

(8) 2 d + 2 e + 2 f + 3 g = 210. 2d + 2e + 2f + 3g = 210.

Solving g from equation (7) and (8) gives us

g = 40. g = 40.

I added in the LaTeX brackets to make the equations look nicer. I like how you don't just give the lines but actually explain what is substituting / subtracting / etc. It's the sort of thing many people abbreviate but it makes the solution easier/faster to read.

Jason Dyer Staff - 4 years, 5 months ago

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...