During the World War 1, the Germans suffered heavy casualties.
65% of the tanks lost their guns,
75% lost their commander, and
85% lost their track.
If every tank lost at least one of the commander, the gun, or the track, and 15% lost exactly one of these, how many lost all three?
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Let a, b, c, d, e, f, and g as follows:
Thus,
(1) a + d + f + g = 6 5 [65% of the tanks lost their guns]
(2) b + e + f + g = 7 5 [75% lost their commander]
(3) c + d + e + g = 8 5 [85% lost their track]
(4) a + b + c = 1 5 [15% lost exactly one]
(5) a + b + c + d + e + f + g = 1 0 0 [total]
Adding the equations (1), (2), and (3) yields:
(6) a + b + c + 2 d + 2 e + 2 f + 3 g = 2 2 5 .
Subtracting equation (5) in from equation (6) yields
(7) d + e + f + g = 1 2 5 .
Substituting equation (4) in equation (6) yields
(8) 2 d + 2 e + 2 f + 3 g = 2 1 0 .
Solving g from equation (7) and (8) gives us
g = 4 0 .