Would you believe it's from NMTC 2K15
3 + 1 − 1 3 + 3 + 1 + 1 3 = ?
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3 solutions
3 + 1 − 1 3 + 3 + 1 + 1 3 = ( 3 + 1 − 1 ) ( 3 + 1 + 1 ) 3 ( 3 + 1 + 1 ) + 3 ( 3 + 1 − 1 ) = 3 + 1 − 1 2 3 ( 3 + 1 ) = 2 3 + 1
Therefore, the answer is: None of the above
rationalize the fractions after taking the LCM .. the problem will get simplified to only numerator (the portion shown in the denominator)....hence none of these
Let a = 3 + 1 . Then 3 + 1 − 1 3 + 3 + 1 + 1 3 = a − 1 a − 1 + a + 1 a − 1 = a − 1 ( a − 1 ) ( a + 1 ) + a + 1 ( a − 1 ) ( a + 1 ) = ( a + 1 ) + ( a − 1 ) = 2 a = 2 3 + 1 The given values in the choices are not equal to this value, hence none of the choices .