Given 1 + x + x 2 + x 3 + x 4 + ⋯ = 2 0 1 7 then x = ?
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1 + x + x 2 + x 3 + x 4 + ⋯ = 1 − x 1 = 2 0 1 7 geometric series with ratio x and infinite sum.
⟹ x = 2 0 1 7 2 0 1 6 .
Another solution: the above expression is x + x 2 + x 3 + ⋯ = 2 0 1 7 − 1 = 2 0 1 6
x ( 1 + 2 0 1 6 ) = 2 0 1 6 ⟹ x = 2 0 1 7 2 0 1 6
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1 + x + x 2 + x 3 + x 4 + ⋯ ⟹ 1 + x ( 1 + x + x 2 + x 3 + ⋯ ) ⟹ 1 + 2 0 1 7 x ⟹ x = 2 0 1 7 = 2 0 1 7 = 2 0 1 7 = 2 0 1 7 2 0 1 6