X in the Matrix

Algebra Level 3

Let A = x 1 y 2 x y 4 y 3 x A = \left|\begin{matrix}x & 1 & y \\ 2 & xy & 4 \\ y & 3 & x \end{matrix}\right| and B = x 2 y 4 x y 3 y 2 x B = \left|\begin{matrix}x & 2 & y \\ 4 & xy & 3 \\ y & 2 & x \end{matrix}\right| .

If the determinant of matrix A A is 3500 3500 and the determinant of matrix B B is 3528 3528 , and x x and y y are real numbers, find x + y x + y .


The answer is 17.

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1 solution

David Vreken
Feb 14, 2018

If the determinant of matrix A A is 3500 3500 , then x 3 y y 3 x 14 x + 10 y = 3500 x^3y - y^3x - 14x + 10y = 3500 .

If the determinant of matrix B B is 3528 3528 , then x 3 y y 3 x 14 x + 14 y = 3528 x^3y - y^3x - 14x + 14y = 3528 .

Solving this system for real numbers gives x = 10 x = 10 and y = 7 y = 7 , and x + y = 10 + 7 = 17 x + y = 10 + 7 = \boxed{17} .

Is there no way to solve this without finding the expressions for each of these determinants?

Pi Han Goh - 3 years, 3 months ago

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Not that I know of. Hopefully someone will surprise us with a different solution!

David Vreken - 3 years, 3 months ago

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