Let A = ∣ ∣ ∣ ∣ ∣ ∣ x 2 y 1 x y 3 y 4 x ∣ ∣ ∣ ∣ ∣ ∣ and B = ∣ ∣ ∣ ∣ ∣ ∣ x 4 y 2 x y 2 y 3 x ∣ ∣ ∣ ∣ ∣ ∣ .
If the determinant of matrix A is 3 5 0 0 and the determinant of matrix B is 3 5 2 8 , and x and y are real numbers, find x + y .
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Is there no way to solve this without finding the expressions for each of these determinants?
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Not that I know of. Hopefully someone will surprise us with a different solution!
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If the determinant of matrix A is 3 5 0 0 , then x 3 y − y 3 x − 1 4 x + 1 0 y = 3 5 0 0 .
If the determinant of matrix B is 3 5 2 8 , then x 3 y − y 3 x − 1 4 x + 1 4 y = 3 5 2 8 .
Solving this system for real numbers gives x = 1 0 and y = 7 , and x + y = 1 0 + 7 = 1 7 .