y^2 - 5y + 6

Probability Level pending

Determine in the set of power series R[[x]] the coefficient of y^5 in the inverse of polynomial y^2 - 5y + 6. Give your answer in 3 decimals.


The answer is 0.014.

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1 solution

Kees Vugs
Aug 15, 2018

1 y 2 5 y + 6 \frac{1}{y^2 - 5y + 6} = 1 y 2 \frac{1}{y - 2} x 1 y 3 \frac{1}{y - 3} = A y 2 \frac{A}{y - 2} + B y 3 \frac{B}{y - 3} = A ( y 3 ) + B ( y 2 ) ( y 2 ) ( y 3 ) \frac{A(y - 3) + B(y - 2)}{(y - 2)(y - 3)} . Thus A + B = 0, -3A - 2B = 1 or A = -1, B = 1. 1 y 2 \frac{- 1}{y - 2} + 1 y 3 \frac{1}{y - 3} = 1 2 \frac{1}{2} x 1 1 y / 2 \frac{1}{1 - y/2} - 1 3 \frac{1}{3} x 1 1 y / 3 \frac{1}{1 - y/3} = [(2^-1) - (3^-1)] x y^0 + [(2^-2) - (3^-2)] x y^1 + . . . + [(2^-6) - (3^-6)] x y^5 + . . .. And [(2^-6) - (3^-6)] = .014.

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