Year 2016

Algebra Level 2

x ( x + 5 ) 2016 ( x 3 ) 2017 ( 6 x ) 1231 ( x 2 ) 10000 ( x + 1 ) 2015 ( 4 x ) 242 0 \dfrac{x{(x+5)}^{2016}{(x-3)}^{2017}{(6-x)}^{1231}}{{(x-2)}^{10000}{(x+1)}^{2015}{(4-x)}^{242}} \geq 0

Find all the possible values of x x .

Clarification : In the options, \cup stands for union.

{ 5 } ( 1 ; 0 ] [ 3 ; 4 ) ( 4 ; 6 ] \{-5\}\cup\left(-1;0\right]\cup\left[3;4\right)\cup\left(4;6\right] ( , 1 ) [ 0 , 2 ) ( 2 , 3 ] [ 6 , ) (-\infty,-1) \cup [0,2)\cup (2,3] \cup [6,\infty) R { 6 } \mathbb R \setminus\{6\} ( , 5 ) [ 2 , 5 ) ( 3 , 7 ] [ 8 , ) (-\infty,-5) \cup [2,5) \cup (3,7] \cup [8,\infty)

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1 solution

![](https://ds055uzetaobb.c

Answer:- option 1

0 ko exclude kyo kiya....uspe to off power hai to sign change hona chahiye na

FAKE GAMER - 9 months, 2 weeks ago

@FAKE GAMER include kia to hai answer mein?

Aryan Sidhwani - 8 months, 4 weeks ago

won't the curve go down at 0 since at x=0 the power is 1 hence odd?

Ashutosh Naruka - 8 months, 3 weeks ago

since the power of 0 is 1 isnt that odd wont the curve go down

devika nb - 7 months, 2 weeks ago

Hello guys correct option is option 1.

Swaroop Naik - 1 month, 3 weeks ago

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