Yearly polynomial

Algebra Level 4

Consider the following polynomial:

f ( x ) = i = 0 2015 a i x 2 i f(x)=\sum_{i=0}^{2015} a_ix^{2i}

The sequence { a i } i = 0 i = 2015 \{a_i\}_{i=0}^{i=2015} is a sequence of arbitrary constants for f ( x ) f(x) .

Find the sum of all real \textbf{real} roots of the given polynomial.


Warning: \textbf{Warning:} You cannot just use Vieta to conclude your answer since we are asked for sum of real \textbf{real} roots.

2015 0 π \pi 1729

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1 solution

Prasun Biswas
Mar 15, 2015

Hint: f ( x ) = f ( x ) x R f(x)=f(-x)~\forall x\in\mathbb{R}

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