These Timelines Are So Confusing

Algebra Level 1

Seven years ago, my mother was seven times older than me.

In exactly eight years from now, my mother will be two times older than me.

How old is my mother now?

25 26 27 28

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2 solutions

Hung Woei Neoh
May 4, 2016

Let your age be x x , and your mother's age be y y .

Seven years ago, my mother was seven times older than me:

y 7 = 7 ( x 7 ) y-7 = 7(x-7) \implies Eq. (1)

In exactly eight years from now, my mother will be two times older than me:

y + 8 = 2 ( x + 8 ) y+8=2(x+8) \implies Eq. (2)

Now, we just need to solve the simultaneous equations:

From Eq. (1):

y 7 = 7 x 49 y-7=7x-49

y = 7 x 42 y=7x-42\implies Eq. (3)

Substitute Eq. (3) into Eq. (2):

7 x 42 + 8 = 2 x + 16 5 x = 50 x = 10 7x-42+8=2x+16\\ 5x=50\implies x=10

Use this value to find your mother's age:

y + 8 = 2 ( 10 + 8 ) y = 28 y+8=2(10+8)\\ y=\boxed{28}

Goh Choon Aik
May 5, 2016

Using logic, we can deduce the mother's age.

In the second line, 'In exactly eight years from now, my mother will be two times older than me.', we can deduce that the age must be an even number, because when 8 is added to the age the total must be divisible by 2.

This rules out 25 and 27.

The first line states that 'Seven years ago, my mother was seven times older than me.' This means that 7 years ago, the mother's age was divisible by 7.

( 26 7 ) m o d 7 = 5 (26 - 7) mod7 = 5

( 28 7 ) m o d 7 = 0 (28 - 7) mod7 = 0

Therefore the mother's age now is 28.

Ah, nice way to do it

Hung Woei Neoh - 5 years, 1 month ago

A faster way is to just subtract 7 from each of them and see if its divisible by 7. You can straight away see it's 28.

Finn C - 5 years, 1 month ago

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which is exactly what i did, except in a more sophisticated way

i just added in the part where the mother's age was even for completedness

Goh Choon Aik - 5 years, 1 month ago

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