and , respectively, are joined as shown. Find the area of the yellow region.
Three squares with side lengths
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The area of the yellow region is equal to the sum of the areas of the three squares minus the sum of the areas of the four triangles. We have, 7 2 + 5 2 + 3 2 − 2 1 ( 1 5 ⋅ 7 + 7 ⋅ 2 + 5 ⋅ 2 + 3 ⋅ 3 ) = 1 4 .