A blue light shines on a yellow shirt in an otherwise dark room.
What color does the shirt appear?
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
When I read the question I first though about the teeshirt turning white in the blue light but there was no way to pick white in the list and for me, Black felt counter-intuitive when you're considering colour subtraction. For the shirt to appear black, it has to be black in the first place. Just to be sure, I tried flashing some blue LED's on a yellow surface. The part of the surface touched by the blue light was white! So either this problem is wrong or I did something wrong, but what ?
Log in to reply
Oh, i would like to know that too.
Yeah, I did the same thing and nothing looked darker (ei. black). My only thought is that either the light source has some extra wavelengths or the yellow surface isn't completely yellow like it's some percentage white but still looks yellow, or both.
My English is bad, I thought that when blue overlap the yellow lol, ahahah And I answered green
Respected Sir and everyone , Please excuse me for posting this comment . Rather than saying that this is a comment this a burning issue in my heart . Please take it seriously .
I have a dream getting 100 or more up votes for an individual solution . I wrote a solution for the question water shadows (which is adjacent to this question) 6 days ago (on 21 April) . When I wrote the solution I thought it is a good one and will definitely accomplish my dream .
I am extremely happy when I saw that the question is in one of the problems of the week . I thought I am nearer to my dream because nobody posted any solution at that time expect me to this question and my solution is a clear and good one . But after these four days I am extremely sad because even more than 11,000 people solved that question only 83 people are discussing solutions . As a result at present I am only left now with 45 up votes . Although my solution deserves more than 100 up votes due silly reasons it is unable to accomplish my dream .
At first when I solved this question (infinite squares) on Monday morning I solved in the manner you did . I thought to post the solution but when I saw you have already posted the same solution (and now you got 299 up votes) . But I didn't worry at that time because I had hope that my solution to water shadows question will definitely cross 100 up votes .
Once see the up votes to the top solutions for the 5 questions of the problems of this week and see how odd it looks :
Infinite squares - Jason Dyer - 349 up votes
Water shadows - Ram Mohith - 57 up votes (see how odd it looks)
Third problem - Zain Majumder - 167 up votes
Fourth problem - Jeremy Galvagni - 129 up votes
Fifth problem - Micheal Mendrin - 250 upvotes
My point is that please try to discuss solutions to every question you solved and try to up vote the solution you admire as much as possible . If you do that many people like me will acheive what they deserve .
Please try to understand my problem .
Log in to reply
Good luck !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!You are a man
One thing I want to point out: while red and green light are commonly combined to yield light that appears yellow to our eyes, this does not mean that yellow light a la the rainbow is a combination of red and green. Yellow light has its own distinct wavelength, between those of red and green. It's merely a convenience that red and green can be combined to stimulate our long and medium-wavelength opsins in a way that mimics how yellow light alone stimulates them. Everything else you wrote is correct.
Yellow objects only reflect red and green light. Blue light is not reflected so no light is reflected by the shirt making it look black.
Oh really? This page seems to show the phenomenon differently.
https://www.quora.com/What-happens-to-a-flower-when-light-of-different-colour-falls-on-it
The problem should point out the colors must be perfectly balanced which is really hard to do in reality.
Log in to reply
I feel the page you link confuses blue light with teal light as it is called in the Venn diagram of the problem. Especially the background colour of the image on the second row is very teal-like, perhaps even a tad greenish.
Also some dyes are fluorescent which might mean that instead of simply absorbing the blue light, the blue light excites the dyes and they emit green light (~530 nm) in response. So in practice, colours are definitely not as trivial as the Venn diagram for combining light sources suggests.
Thank you. That is exactly what I thought.
Wouldn't the shirt absorb the blue light, making it yellow?
Log in to reply
There are monochromatic (only one wavelength of light) sources if light but no monochromatic pigments.
After absorbing the blue light, the light is converted into heat. The shirt will light up in infra-red (which our eyes cannot see). Therefore the shirt will appear black.
I tried the experiment out and it showed a greenish looking color. I wonder how the light is black though. I would rate this problem an 8 because I didn't really understand it.
In the real world, using various 'blue' lights and various 'yellow' materials, then 'black' will happen more often than pure yellow, green or blue. However the most common result would likely be a very dark blue or green.
The 'logic' of the question is workable, but only if you correctly anticipate the assumptions the questioner has made - which are not the only viable assumptions that result in one of the allowed answers.
Alternate correct assumptions and answers are:
1) Blue - Assume the light source is a mix of "blue" wavelengths. Assume the shirt is yellow because it includes reflected green and red threads. Assume the wavelengths of the green threads overlap with the blue cones of the human eye. The result will be that the shirt will reflect some of the blue wavelengths, resulting in a blue shirt.
2) Green - Basically the same scenario as above, except the reflected wavelengths predominantly are in the green cone spectrum.
3) Yellow - Assume the shirt absorbs blue light and emits yellow light.
4) Green, Yellow, or Blue - Assume the shirt's color includes thin film interference. The result (depending on exactly what wavelengths are in the 'blue' light and exactly what TFI is happening), could be green or yellow or blue.
If the "yellow" shirt had significant blue light reflectivity, then we can assume it would appear grey or white instead of yellow under normal (i.e. white) lighting conditions.
Log in to reply
Yes, and there are many other colors the shirt could appear to be in a blue light as well. My answer addresses only the colors offered as valid by the questioner.
Its worth noting that in movies that are simulating night vision, where there are colors, but they are washed out, they use blue lighting.
Speaking as a lighting designer, this top comment is closer to the truth. The dyes and threads used in colors is always unpredictable and a yellow shirt will always have some general reflectivity. Having seen many yellow shirts onstage under blues, I can say they look weird but definitely never black. In fact, they often fluoresce. Not a great question.
So many science questions are like this, especially physics. If you make just the right assumptions you can argue for the answer you want.
Log in to reply
Thus the art of constructing useful questions. When you find a question particularly challenging - yet logic leads to one of the answers and no where else - then be sure to 'Like' the question. Unfortunate that there's no down vote for poorly constructed challenges like this one.
https://www.youtube.com/watch?v=ol529s_gUIc hope this answers the question........ (ps not my video)
Log in to reply
This video is not definitive - you'll find other videos showing different results depending on the materials and the frequencies of illumination being used.
Also note that this video uses the term 'reflected' in its broadest sense, as any light that is not coming from behind the material. Yet it's claiming that in all cases, PERCEIVED color is determined by subtraction - ignoring the effects of interference, diffraction, re-emission and so on. Most importantly, perception is manipulated by the stimulation thresholds of the cones and interpretation effects in the brain (remember the gold/black dress meme?).
Nicely explained. I think the question has an implicit hypothesis that the light is monochromatic. That should be made explicit.
Yellow objects reflect yellow light (which is a mixture of red and green light) but don’t reflect any other color (like blue light). Since it doesn’t reflect blue light, and blue light is the only light in the room... there wouldn’t be any light reflected to our eyes! And since a lack of light is represented by our eyes as black, the shirt would appear black.
Good strategy!
On a side note, most of are taught misinformation in art class. We are taught that the 3 primary pigments are red, yellow, and blue. Technically the 3 primary subtractive colors (i.e. pigments) are magenta, yellow, and cyan (teal in this case). The primary subtractive colors are also the secondary additive colors. The primary additive colors (i.e. light) are red, green, and blue. It is conventional to assume additive unless otherwise specified. Therefore the primary colors are technically red, green, and blue.
Under colored most of objects appear to be of the same color as that of the object or may appears Black .So a yellow object under white light will absorb most of the colours of light, and reflect back the yellow light, so we can see yellow.
As yellow light is a mixture of red and green light, yellow will also reflect red and green light. This means that a yellow object will appear red under red light, and green under green light. .Since it is not a mixture of Blue light it wont appear Blue , Rather it will appear black.
just because the room is dark , it reflect no color to our eyes so it's turn to black
The question says that blue light shines on the shirt, and no other light shines on the shirt.
yellow colour of the shirt! THIS MEANS THAT shirt absorbs all the colours except yellow(it reflects it). so,blue is absorbed by the shirt when it is shined on it, and reflected is NOTHING(or BLACK).
I accidentally clicked the wrong solution Im really angry
When an object appears to be a certain color, it is absorbing every color BUT the color it appears.
In this case, when we shine a blue light, on an object that only reflects yellow light, all of the blue light will be absorbed and none of it will be reflected. When no light is reflected, it appears to our eyes to be black.
From the knowledge of basic colours we know that....yellow +blue =green..again green +green =green...and red +green =is perhaps black
Problem Loading...
Note Loading...
Set Loading...
The Venn diagram shows what mixing various lights (as opposed to paints) looks like. For example, yellow light is simply a mixture of red and green color light wavelengths. If a shirt is yellow, this means that it reflects yellow light, which by extension means that it will reflect red and green light. However, yellow light is not made up of any blue light, which means the shirt absorbs blue light.
If all the light shining on the shirt is blue, all light will be absorbed. Therefore, the shirt would appear black.