z 3 + ∣ z ∣ 3 ( z ) 2 = 0
How many complex numbers satisfy the above equation?
Notations:
z denotes the complex conjugate of z .
∣ z ∣ denotes the absolute value of z .
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The Question says z 2 , not z 3
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Sorry bro. I have changed it. my greatest apologies
Note that z × z = ∣ z ∣ 2 .
Observe that z = 0 is not a solution (the second term is not defined). Now multiply both sides by z 2 to obtain:
z 5 + ∣ z ∣ 3 z 2 z 2 z 5 + ∣ z ∣ 3 ∣ z ∣ 4 z 5 + 3 ∣ z ∣ 3 z 5 = 0 = 0 = 0 = − 3 ∣ z ∣ 3
Taking the modulus of each side, we have ∣ z ∣ 5 = 3 ∣ z ∣ 3 , or ∣ z ∣ 2 = 3 (because ∣ z ∣ = 0 ). Since ∣ z ∣ > 0 , we have ∣ z ∣ = 3 . Thus we obtain z 5 = − 3 5 / 2 , giving 5 solutions for z : − 3 1 / 2 times each fifth root of unity.
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