An algebra problem by neelesh vij

Algebra Level 5

z 3 + 3 ( z ) 2 z = 0 \large z^{3} + \frac{3 (\overline{z})^{2} } {|z|} = 0

How many complex numbers satisfy the above equation?

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6 7 3 5 11 10 8 4

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2 solutions

Neelesh Vij
Feb 6, 2016

The Question says z 2 z^2 , not z 3 z^3

Hargun Preet Singh - 5 years, 4 months ago

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Sorry bro. I have changed it. my greatest apologies

neelesh vij - 5 years, 4 months ago
Ivan Koswara
Apr 22, 2017

Note that z × z = z 2 z \times \overline{z} = |z|^2 .

Observe that z = 0 z = 0 is not a solution (the second term is not defined). Now multiply both sides by z 2 z^2 to obtain:

z 5 + 3 z 2 z 2 z = 0 z 5 + 3 z 4 z = 0 z 5 + 3 z 3 = 0 z 5 = 3 z 3 \begin{aligned} z^5 + \frac{3 z^2 \overline{z}^2}{|z|} &= 0 \\ z^5 + \frac{3 |z|^4}{|z|} &= 0 \\ z^5 + 3|z|^3 &= 0 \\ z^5 &= -3|z|^3 \end{aligned}

Taking the modulus of each side, we have z 5 = 3 z 3 |z|^5 = 3 |z|^3 , or z 2 = 3 |z|^2 = 3 (because z 0 |z| \neq 0 ). Since z > 0 |z| > 0 , we have z = 3 |z| = \sqrt{3} . Thus we obtain z 5 = 3 5 / 2 z^5 = -3^{5/2} , giving 5 \boxed{5} solutions for z z : 3 1 / 2 -3^{1/2} times each fifth root of unity.

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