Yet another question 8

Calculus Level 5

min x R max 0 y 1 y 2 x y \displaystyle\large{ \min_{x \in \mathbb{R}} \max_{0 \le y \le 1} |y^2 - xy| }

Find the value of the expression above.


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3 8 -3 - \sqrt{8} 1 4 \dfrac 14 1 1 3 8 3 - \sqrt{8} 1 2 \dfrac 12 2 8 -2 - \sqrt{8} 2 8 2 - \sqrt{8}

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1 solution

Someone Please explain me this:

If I assume x = 0 x=0 .

And we take y = 1 / n y=1/n where n ϵ N n \epsilon N .

Now if we take n approaching infinity therefore expression approaches zero.

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