Yet another straightforward Differentiation

Classical Mechanics Level 1

Angular momentum of an particle depends on time as ; L = 3 t 2 + 4 t − 5 L = 3t^2 +4t-5 .

Find torque acting on particle at t = 1 sec ⁡ . t=1\sec.


The answer is 10.

A Former Brilliant Member by A Former Brilliant Member

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Torque is other wise called as rate of change of angular momentum.

∵ τ = d L d t = d d t ( 3 t 2 + 4 t − 5 ) ⟹ τ = 6 t + 4. ⟹ ( τ ) t = 1 = 6 × 1 + 4 = 6 + 4 = 10 . \large \displaystyle \because \tau = \frac{dL}{dt} = \frac{d}{dt} (3t^2 + 4t - 5)\\ \large \displaystyle \implies \tau = 6t + 4.\\ \large \displaystyle \implies \left( \tau \right)_{t=1} = 6 \times 1 + 4 = 6 + 4 = \color{#3D99F6}{\boxed{10}}.

6 Helpful 0 Interesting 0 Brilliant 0 Confused

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...