Yin Yang

Geometry Level 3

Diameter ACE is divided at C in the ratio 2:3 The two semicircles, ABC and CDE, divide the circular region into an upper (shaded) region and a lower region. The ratio of the area of the upper region to that of the lower region can be expressed as a b \frac{a}{b} , where a a and b b are coprime positive integers. What is the value of a + b a+b ?


The answer is 5.

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2 solutions

Daniel Liu
Jun 7, 2014

To simplify calculations, let the formula f ( d ) f(d) of the area of a semicircle given diameter d d be f ( d ) = c d 2 f(d)=cd^2 for a constant c c .

We see that the area of the black region is 25 c + 9 c 4 c = 30 c 25c+9c-4c=30c and the area of the white region is 25 c + 4 c 9 c = 20 c 25c+4c-9c=20c .

Thus the ratio is 30 c 20 c = 3 2 \dfrac{30c}{20c}=\dfrac{3}{2} so our answer is 3 + 2 = 5 3+2=\boxed{5} .

Someone reported this problem wrong.

Mardokay Mosazghi - 7 years ago

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The report stated "It does not say to find the sum of a and b at the end." which is a valid clarification. I've since updated your question to reflect asking for a + b a+b .

Calvin Lin Staff - 7 years ago

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Thanks and sorry about that @Calvin Lin

Mardokay Mosazghi - 7 years ago
Unstable Chickoy
Jun 17, 2014

Let

A u A_u = Area upper region

A l A_l = Area lower region

A t A_t = Total area

Assume the radius of the circle is r = 10 r = 10 .

A u = 5 2 π 2 2 2 π 2 + 3 2 π 2 = 15 π A_u = \frac{5^2\pi}{2} - \frac{2^2\pi}{2} + \frac{3^2\pi}{2} = 15\pi

A l = A t A u = 5 2 π 15 π = 10 π A_l = A_t - A_u = 5^2\pi - 15\pi = 10\pi

A u A l = 15 π 10 π = 3 2 \frac{A_u}{A_l} = \frac{15\pi}{10\pi} = \frac{3}{2}

a + b = 3 + 2 = 5 a + b = 3 + 2 =\boxed{5}

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