Yo Yo Honey Singh....!!!

Computer Science Level 1

Observe the following coding in java. Can you find the number of times "yo yo honey singh" will be displayed? 

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for(int i=0;i--<=5;i++)
     {
           System.out.println("Yo Yo Honey Singh");
      }

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five times infinite times ten times one time

Raj Maiti by Raj Maiti , 23, India

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3 solutions

Sonali Srivastava
Jul 18, 2014

i is initialized with a value 0 in condition i--<=5 n update is i++ 1st time i=0,(i--) -1<=5 loop executes then i++ makes i=0 but in 2nd execution of the loop i-- again makes i=-1 thus value of i is always -1 due to i-- n 0 due to i++ hence it executes infinitely

1 Helpful 1 Interesting 0 Brilliant 0 Confused
Monikrishna Roy
May 22, 2014

first i=0, then for i--, i is -1, then for i++, i is 0

for this i is always 0 and 0<=5 , so , this program print this line infinite times.

2 Helpful 0 Interesting 0 Brilliant 0 Confused

I think as it is postfix operator so immediately i-- does not change to -1... i value remains 0 always.. so infinite number of times it will run.

Arijit Banerjee - 7 years ago
Jasveen Sandral
May 23, 2014

It's easy cause she wrote i---------------

0 Helpful 0 Interesting 0 Brilliant 0 Confused

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