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Solve the poblem in base 5

2 5 15 + 4 5 14 + 5 13 + 3 5 12 + 2 5 11 + 2 5 10 2*5^{ 15 }+{ 4*5 }^{ 14 }{ +5 }^{ 13 }+{ 3*5 }^{ 12 }+{ 2*5 }^{ 11 }+{ 2*5 }^{ 10 } + 4 5 9 + 3 5 8 + 5 7 + 2 5 6 + 3 5 5 +{ 4*5 }^{ 9 }+{ 3*5 }^{ 8 }+{ 5 }^{ 7 }+{ 2*5 }^{ 6 }+{ 3*5 }^{ 5 } + 4 5 4 + 5 3 + 5 2 + 19 +{ 4*5 }^{ 4 }+5^{ 3 }+{ 5 }^{ 2 }+19


The answer is 2413224312341134.

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2 solutions

Chew-Seong Cheong
Sep 25, 2015

Let the number to be found be in based 5 5 be N 5 N_5 , then we have:

N 5 = 2 ˙ 5 15 + 4 ˙ 5 14 + 3 ˙ 5 13 + 5 12 + 2 ˙ 5 11 + 2 ˙ 5 10 + 4 ˙ 5 9 + 3 ˙ 5 8 + 5 7 + 2 ˙ 5 6 + 3 ˙ 5 5 + 4 ˙ 5 4 + 5 3 + 5 2 + 19 = 2 ˙ 5 15 + 4 ˙ 5 14 + 3 ˙ 5 13 + 1 ˙ 5 12 + 2 ˙ 5 11 + 2 ˙ 5 10 + 4 ˙ 5 9 + 3 ˙ 5 8 + 1 ˙ 5 7 + 2 ˙ 5 6 + 3 ˙ 5 5 + 4 ˙ 5 4 + 1 ˙ 5 3 + 1 ˙ 5 2 + 3 ˙ 5 1 + 4 ˙ 5 0 [ 19 = 15 + 4 ] = 241322431234113 4 5 \begin{aligned} N_5 & = 2\dot{}5^{15} + 4\dot{}5^{14} + 3\dot{}5^{13} + \color{#3D99F6}{5^{12}} + 2\dot{}5^{11} + 2\dot{}5^{10} + 4\dot{}5^{9} + 3\dot{}5^{8} \\ & \quad + \color{#3D99F6}{5^{7}} + 2\dot{}5^{6} + 3\dot{}5^{5} + 4\dot{}5^{4} + \color{#3D99F6}{5^{3}} + \color{#3D99F6}{5^{2}} + \color{#D61F06} {19} \\ & = 2\dot{}5^{15} + 4\dot{}5^{14} + 3\dot{}5^{13} + \color{#3D99F6}{1\dot{} 5^{12}} + 2\dot{}5^{11} + 2\dot{}5^{10} + 4\dot{}5^{9} + 3\dot{}5^{8} \\ & \quad + \color{#3D99F6}{1\dot{}5^{7}} + 2\dot{}5^{6} + 3\dot{}5^{5} + 4\dot{}5^{4} + \color{#3D99F6}{1\dot{} 5^{3}} + \color{#3D99F6}{1\dot{} 5^{2}} + \color{#D61F06} {3\dot{}5^1 + 4\dot{}5^0} \quad \quad \color{#D61F06}{[19 = 15+4]} \\ & = \boxed{2413224312341134_5} \end{aligned}

Aaaaa Bbbbb
Sep 20, 2015

It Is very clear to get the following expressions: 5 = 10 5=10 5 2 = 100 5^2=100 2 × 5 15 = 2000000000000000 2 \times 5^{15} = 2000000000000000 4 × 5 14 = 400000000000000 4 \times 5^{14} = 400000000000000 5 13 = 10000000000000 5^{13} = 10000000000000 3 × 5 12 = 3000000000000 3 \times 5^{12} = 3000000000000 2 × 5 11 = 200000000000 2 \times 5^{11} = 200000000000 2 × 5 10 = 20000000000 2 \times 5^{10} = 20000000000 4 × 5 9 = 4000000000 4 \times 5^{9} = 4000000000 . . . . . . . . . . . . . . . . . . . . . . . . . . . ........................... 19 = 45 19=45 So: R e s = 2413224312341134 Res = \boxed{2413224312341134}

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