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Algebra Level 1

If 10^x=64, what is 10^(x/2 + 1) ???

No answer 64 80 100

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2 solutions

William Martin
Oct 26, 2014

Use log (base 10) to drop the power of x and make the 10 disappear... you then have x = log 64 ... from there the rest falls in to place

10^x=64 10^x=8^2 =10^x 1/2 * 10^1 =64^1/2 10= 8*10= 80 hence 10^(x/2+ 1)= 80

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