What is the sum of the first 2 0 1 6 even numbers .
Important: The first even number will be 2 .
This problem is inspired with the "odd version of this", which is probably not original.
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Sum of first n even numbers only n(n+1).You hasn't mentioned it.Please mention it
This can be done by using Arithmatic Progression
Solution:
Mathematical induction:
S ( 1 ) = 2 ;
S ( 2 ) = 2 + 4 = 6 ;
S ( 3 ) = 2 + 4 + 6 = 1 2 ;
. . .
It seems that S ( n ) = n ( n + 1 ) . If so, then: S ( n + 1 ) = 2 + 4 + . . . + 2 n + 2 n + 2 = n ( n + 1 ) + 2 ( n + 1 ) = = ( n + 2 ) ( n + 1 ) .
Therefore, the solution is 2 0 1 6 × 2 0 1 7 = 4 0 6 6 2 7 2 .
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→ Sum of first n even numbers = n ( n + 1 )
⇒ 2 0 1 6 × 2 0 1 7 = 4 0 6 6 2 7 2