Is 2 5 7 8 8 5 1 6 1 − 1 a prime number, or not?
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2^odd number - 1 is always a prime number.Since the given power is odd
therefore the given number is a prime number.
What about 2 9 − 1 , it is 5 1 1 . Which has divisors - 1 , 7 , 7 3 , 5 1 1
One could argue your sentence in two different ways. 1. IF the exponent k is composite, THEN the number 2^k-1 is composite. Since an odd number isn't necessarily prime, you are wrong. 2 At this point you could say that for k prime, 2^k-1 is prime, too, but also saying this would be an error. We currently don't even know if there are infinite primes in the form of 2^p-1, and the relative hypothesis is known as Mersenne (open) conjecture. So definitely nope. That's not true.
so is there any logical answer for this qeustion other than geussing. for 2^11-1 the prime factors are 23*89.. we can observe 23 and 89 both are prime numbers. if we think that 2^n-1 in such form that n being a prime no.{ which is not applicale for n=11}
whnevr 2 is wid a pwr of of an odd integer nd we subtrct 1 frm it we wll get a prime nmbr..for eg.. 2^3 -1=7 2^5-1=31 2^7-1=127
Read my comment above.
It is the largest found Mersenne Prime, that is a prime number in the form of 2 n − 1
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Greatest Internet Mersenne Prime Search, or GIMPS, is a collaborative project in which people try and break the world record for the largest known prime. The number shown is currently the largest prime known as of 2014.