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Calculus Level 1

d d x ln ( x ) = ? \large \frac{d}{dx}\ln(x) = ?

x 1 x^{-1} x 1 2 x^{-\frac{1}{2}} x 2 x^{-2} x \sqrt{x}

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1 solution

CodeCrafter 1
Nov 10, 2019

You can prove this by using implicit derivation. f ( x ) = l n ( x ) e f ( x ) = x f \left( x \right) = ln \left( x \right) \\ e^{f \left( x \right)} = x By deriving it, we get: e f ( x ) f ( x ) = 1 x f ( x ) = 1 e^{f \left( x \right)} \cdot f' \left( x \right) = 1 \\ x \cdot f' \left( x \right) = 1 Now devide by x x and you get:

f ( x ) = 1 x \boxed{ f' \left( x \right) = \frac{1}{x} }

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