Yummy Jelly

Algebra Level 1

A jelly shop sells its products in two different sets: 3 red jelly cubes and 3 green jelly cuboids.

The 3 red cubes are of side lengths a < b < c , a<b<c, while the 3 green cuboids are identical with dimensions a × b × c , a\times b\times c, as shown above.

Which option would give you more jelly?

The three red jellies The three geen jellies They are both equal. No definite relation can be made.

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2 solutions

From the given information, obviously the volume of the red jelly = a 3 + b 3 + c 3 a^3 + b^3 + c^3 .

On the other hand, the volume of the green jelly = 3 a b c 3abc .

According to Arithmetric Mean - Geometric Mean Inequality , a 3 + b 3 + c 3 3 a 3 b 3 c 3 3 = a b c \dfrac{a^3 + b^3 + c^3}{3} \ge \sqrt[3]{a^3 b^3 c^3} = abc .

Hence, a 3 + b 3 + c 3 3 a b c a^3 + b^3 + c^3 \ge 3abc .

Since the inequality will become equation if and only if a = b = c a = b = c , the volumes of both jelly sets can never be equal.

As a result, the red jelly will have more volume than the green one.

Moderator note:

Simple standard approach.

Interesting approach, Dr. Warm. I solved it in a slightly different way. We know that a 3 + b 3 + c 3 3 a b c = 1 2 ( a + b + c ) ( ( a b ) 2 + ( b c ) 2 + ( c a ) 2 ) a^3 + b^3 + c^3 - 3abc = \frac{1}{2} (a+b+c) \left( (a-b)^2 + (b-c)^2 + (c-a)^2 \right)

We see that the RHS is positive since a , b , c a, b, c are not all equal. Hence the volume of red jellies is (strictly) greater than the volume of the green jellies.

Pranshu Gaba - 4 years, 11 months ago

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But this is literally in the AM-GM Wiki.

madhavendra thakur - 1 year ago

I did it the same way

Pranav Jayaprakasan UT - 4 years, 4 months ago

We know that AM GM inequality could be proved using Cauchy Induction ( or the Forward Backward induction) but can this approach to induction be applied to the other formulae that we can prove with induction ( weak and strong) or it has no other applications.If the former is true I would like to know how?

Amit Singh - 3 years, 5 months ago
Tisya Rawat
Jan 7, 2021

Sum of the volumes of the three red cubes= a 3 a^{3} + b 3 b^{3} + c 3 c^{3}

sum of volumes of the three green cuboids= abc + abc + abc= 3abc

AM >= GM

( a 3 a^{3} + b 3 b^{3} + c 3 c^{3} )/3 >= cube root ( a 3 a^{3} b 3 b^{3} c 3 c^{3} )

a 3 a^{3} + b 3 b^{3} + c 3 c^{3} >= 3abc

a>b>c so equality is not possible because for equality, a=b=c

therefore a 3 a^{3} + b 3 b^{3} + c 3 c^{3} > 3abc

hence, volume of the three cubes > volume of the three cuboids

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