An anthropomorphic guinea pig decided to go to a barber to be completely shaved. Little did he know that the barber only cuts exactly half of their customer's hair/fur. How many sittings does the guinea pig need to be completely shaved?
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Way too hard to understand. Here's a simpler explanation:::
Let ( a n ) n = 1 n = ∞ be a sequence of numbers in the field a n ∈ R such that it follows a recurrence relation with a n + 1 = 2 1 a n and initial term of a 1 = 2 1 . This shows that we have a geometric progression. Because the common ratio is r = 2 1 with ∣ r ∣ < 1 , we can show that the sum converge by ratio test. Furthermore, we note that limit supremum of this sum is 1, thus the partial sum is always less than 1. Thus you can't achieve the value of 1 by a finite partial sum. Quod Erat Demonstrandum.
Two haircuts. The anthropomorphic pig will not be happy about the half haircut and will find another barber making sure that this barber cut 100%. If everyone was wanting a 50% haircut every time it would be a great business idea.
LOL ....nicely done !
If haircut is H then H= 1/2 + 1/4 + 1/8 + 1/16 + 1/32 etc. so 1/2H= 1/4 + 1/8 + 1/16 + 1/32 etc. so H-1/2H= 1/2H= 1/2 as the rest would cancel out so H=1 so he would get all his hair off eventually although you couldn't apply this to a real life situation since there would be an infinite number of haircuts
Not technically correct since the number of hairs is finite. Even if we consider fractions of hairs the number of atoms in a hair is also finite. Thus the series is not actually infinite.
Clearly we can consider this as an analogy to a true infinite series and it illustrates the concept, however the actual process would be large, but finite. Perhaps I'm just "splitting hairs" here, but it's true :)
Yup. There's literally splitting of hairs here. If there's only ONE hair left, then the barber is going to cut 1/2 of that hair. And the next time, the barber is going to cut 1/4 of that hair and so on.
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Even still. The system remains finite. There are a finite number of atoms in a hair and only a tiny number of elementary particles in the final atom of the hair. The series is certainly long, but, as with any physical system, ultimately finite.
It's still a good problem. I am not disputing that. I was just pointing out that any physical realization of this principle must be only an approximation to a true infinite series since a physical quantity is not infinitely divisible due to quantum considerations.
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Hahahahaha! I see that you have hired a lawyer. Well played!
Whether the barber cuts .0000001% or 99.9999% of the guinea pigs' current amount of fur, he will never completely shave any guinea pig.
In order for the hair to totally be shaved, you'd need to take off 100% each time (once). So long as the proportion that you take off is constant in relation to the fur of the animal, the total amount of hair at shave #X can never be 0.
If H n is the amount of hair amount n shavings and H i = H_0= Hair initially,
Then you'd have H 1 = H i .5, H_2 = H_1 .5 = H_i*.25 and so on....
Since the x in the recurrence relation H_n*x will never be 0,then the total hair after any given shave from this barber will not result in a total loss of hair.
It quite simple....the barbar has a permanent condition to spare half of the hair....leading to infinite number of cuts....
Yes, but for that, don’t you have to established the speed of the regrow?
Well the barber shop has a condition to cut only 1/2 of the hair so it means that no matter how many times the anthropomorphic guinea pig go to the barber shop it will always left 1/2 of the hair.
We can put it in a way; that take the whole as 1. Half of that is 1/2; but for the next sitting; it is gonna be half of that is remaining; but not the whole. So, 1/2 of 1/2 is 1/4... It keeps on continuing to an infinite series; which can never end, thus the guinea pig is not completely shaved.
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i = 1 ∑ n 2 i 1 = 1 ⇒ n = ∞