Zero this, part 2
Algebra
Level
3
Consider the function over all real
How many zeroes does it have?
2
0
3
1
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1 solution
Multiplying out, you get f ( x ) = x 3 + 6 x 2 + 1 1 x
Clearly it has one zero at x = 0. Factoring this out, we are left with x 2 + 6 x + 1 1
Since the discriminant of this quadratic is negative, it has no zeroes. So the total number of zeroes of f ( x ) is 1.