I f α , β a r e z e r o e s o f x 2 − 3 x + 1 = 0 t h e n f i n d t h e v a l u e o f α 2 0 1 5 + β 2 0 1 5 α 2 0 1 4 + β 2 0 1 4 + α 2 0 1 6 + β 2 0 1 6
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aryan saxena Don't write the full question , whenever you write , from starting to beginning in '\ [ ' and '\ ]' instead use it only for expressing the mathematical representations.
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By simplifying the given quadratic equation, we get x 2 0 1 6 + x 2 0 1 4 = 3 x 2 0 1 5 .
Thus, The problem becomes α 2 0 1 5 + β 2 0 1 5 3 ( α 2 0 1 5 + β 2 0 1 5 ) which, easily, is 3 .