Zeroing out, part 3

Algebra Level 3

Let z z be a complex number.

Consider the equation ( z 3 1 ) / ( z 2 + z 2 ) (z^3 - 1) / (z^2 + z - 2) on the complex plane. How many zeroes does it have?

3 2 0 1

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Denton Young
Feb 5, 2016

Factoring: ( z 1 ) ( z 2 + z + 1 ) / ( z 1 ) ( z + 2 ) (z-1)(z^2 + z + 1) / (z-1)(z+2)

0/0 at z = 1. That is not a valid zero. The other two complex zeroes are valid, so it has two zeroes and one removable singularity.

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...