Unusual zeros

If 25 ! 25! divided by 2 22 2^{22} , find the number of trailing zero(s) from the resultant number.


The answer is 0.

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1 solution

Satyajit Ghosh
Jun 25, 2015

25! has 2,4,6,8,10,12,14,16,18,20,22 and 24 as even no.s. If we see 25! has 2^22 as factor. On dividing, we will get the remainder as 0.

We know to form 0 i.e. 10 has to be a multiple so 2 has to be a factor. Here 2 is not left so we cannot have a 0 at the end.

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