Zeros

How many trailing number of zeros does the following product end with?

1000 × 999 × 998 × × 3 × 2 × 1 1000\times 999\times 998\times \cdots \times 3\times 2\times 1


The answer is 249.

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1 solution

Lee Care Gene
Jan 8, 2016

As 5×2 is 10, 25×4 is 100, 125×8 is 1000 and 625×16 is 10000, we divide the number 1000 by 5, 25, 125 and 625, then add up the quotients.

1000/5=200

1000/25=40

1000/125=8

1000/625=1(R)375

Number of zeros=200+40+8+1=249

where is 10 ..20..30..100..200..300..400 ??

حسن الحاج - 5 years, 5 months ago

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It's already counted.

Lee Care Gene - 5 years, 5 months ago

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