What will be the number of trailing zeros in 99! ?
Note: n! = n * (n-1) * . . . . . 3 * 2 * 1
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The number of trailing zeros in a given number can be calculated by dividing the number with 5^n till the quotient is less than one and all the values obtained.Therefore by doing the same for 99 , we get the answer as 19+3 , which is 22