Zeros

5,10,15,20 will create four zeroes ; 25 will create 2 zeroes

Power of 2 in 25! is |25/2|+|25/2^2|+|25/2^3|+|25/2^4|=22. Power of 5 in 25! is |25/5|+|25/5^5|=6. Power of 10 in 25! is 6.

Here is my solution: Look quickly into this multiplication: If numbers end with 5 multiplies with even numbers: 2, 4, 6, 8: The answer will have zeroes at the end.

So we have $2\times 4\times 6\times 8\times 5=1920$ ; $12\times 14\times 16\times 18\times 15=725760$ ; $22\times 24\times 25=13200$ . So we have $\boxed { 4 }$ zeroes here!

But number 10 and 20 will add $\boxed { 2 }$ more zeroes to the value of this multiplication.

So, the total zeroes at the end of the value of 25! are: $4+2=\boxed { 6 }$ !

And the correct answer is 6 !

For every trailing zero, x! Must be divided by five, twenty five and sub. Power of 5. So 25÷5 = 5 25÷25 = 1 So there are 5+1=6 trailing zeros of 25!