Zeta Function with prime-

Find the close form of: p = p r i m e p 4 p 4 + 1 \prod_{p= \rm prime}\frac{p^4}{p^4+1}

ζ ( 8 ) ζ ( 2 ) \frac{\zeta(8)}{\zeta(2)} ζ ( 4 ) \zeta(4) ζ ( 8 ) ζ ( 4 ) \frac{\zeta(8)}{\zeta(4)}

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1 solution

By Euler product , we have:

ζ ( s ) = p = p r i m e 1 1 p s \zeta(s) = \prod_{p=\rm prime} \frac 1{1-p^{-s}}

where ζ ( ) \zeta(\cdot) denotes the Riemann zeta function .

Then

p = p r i m e p 4 p 4 + 1 = p = p r i m e 1 1 + 1 p 4 = p = p r i m e 1 1 p 4 1 1 p 8 = ζ ( 8 ) ζ ( 4 ) \prod_{p=\rm prime} \frac {p^4}{p^4+1} = \prod_{p=\rm prime} \frac 1{1+\frac 1{p^4}} = \prod_{p=\rm prime} \frac {1-\frac 1{p^4}}{1-\frac 1{p^8}} = \boxed{\frac {\zeta(8)}{\zeta(4)}}

Yes that's right @Chew-Seong Cheong sir

Abdulrasheed Bolaji - 7 months ago

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Nice problem

Chew-Seong Cheong - 7 months ago

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