This discussion board is a place to discuss our Daily Challenges and the math and science
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explain the steps and thinking strategies that you used to obtain the solution. Comments
should further the discussion of math and science.
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Math
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2 \times 3
2×3
2^{34}
234
a_{i-1}
ai−1
\frac{2}{3}
32
\sqrt{2}
2
\sum_{i=1}^3
∑i=13
\sin \theta
sinθ
\boxed{123}
123
Comments
I'm sorry to tell you this, but you made a mistake in your calculations: As I answered in a question which was made in Brilliant, there are reasons that lead to 0/0 being undetermined. The problem in the 4th step is that when you went from [(10-10)(10+10)]/10(10-10) to 20/10, you divided the numerator and the denominator by 0. Here is what you did: [(10-10)(10+10)]/10(10-10) = [(10-10)(10+10)/(10-10)]/[10(10-10)/(10-10)], which can be simplified to [(10+10)0/0]/(100/0). Given the fact 0/0 is undefined, you can't replace it with 1, nor any other number. Basically, you can't undo a multiplication with zero by dividing by zero, nor undo a division by zero by multiplying by zero, as both situations result in something similar to a*0/0, in which 0/0 is undefined and can't be replaced by any number, Other implications of 0/0 being undefined are that anything being divided or multiplied by 0/0 is undefined, and that you can't divide anything by an expression which is or can be equal to zero, as the result is undefined in case said expression turns out to be zero. This is why we can't simplify x/x into 1, for example. Here's the reasons why 0/0 is undefined, written by me: https://brilliant.org/discussions/thread/why-00-is-not-define/
Easy Math Editor
This discussion board is a place to discuss our Daily Challenges and the math and science related to those challenges. Explanations are more than just a solution — they should explain the steps and thinking strategies that you used to obtain the solution. Comments should further the discussion of math and science.
When posting on Brilliant:
*italics*
or_italics_
**bold**
or__bold__
paragraph 1
paragraph 2
[example link](https://brilliant.org)
> This is a quote
\(
...\)
or\[
...\]
to ensure proper formatting.2 \times 3
2^{34}
a_{i-1}
\frac{2}{3}
\sqrt{2}
\sum_{i=1}^3
\sin \theta
\boxed{123}
Comments
I'm sorry to tell you this, but you made a mistake in your calculations: As I answered in a question which was made in Brilliant, there are reasons that lead to 0/0 being undetermined. The problem in the 4th step is that when you went from [(10-10)(10+10)]/10(10-10) to 20/10, you divided the numerator and the denominator by 0. Here is what you did: [(10-10)(10+10)]/10(10-10) = [(10-10)(10+10)/(10-10)]/[10(10-10)/(10-10)], which can be simplified to [(10+10)0/0]/(100/0). Given the fact 0/0 is undefined, you can't replace it with 1, nor any other number. Basically, you can't undo a multiplication with zero by dividing by zero, nor undo a division by zero by multiplying by zero, as both situations result in something similar to a*0/0, in which 0/0 is undefined and can't be replaced by any number, Other implications of 0/0 being undefined are that anything being divided or multiplied by 0/0 is undefined, and that you can't divide anything by an expression which is or can be equal to zero, as the result is undefined in case said expression turns out to be zero. This is why we can't simplify x/x into 1, for example. Here's the reasons why 0/0 is undefined, written by me: https://brilliant.org/discussions/thread/why-00-is-not-define/
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Yep!You got it.I already knew this mistake.I like fallacies.
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Me too.