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yea, i got to what you are trying to say......it's great and right.....a good job...then wait for tomorrow for an another great problem......keep in touch....:--]
It can be seen through this... most of the above portion ...
an expression of the form {Asinx +(or -) Bcosx} oscillates between +(-) sqrt(a^2 + b^2) ...
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This discussion board is a place to discuss our Daily Challenges and the math and science related to those challenges. Explanations are more than just a solution — they should explain the steps and thinking strategies that you used to obtain the solution. Comments should further the discussion of math and science.
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since m and l are real .it means that l<1 and m<1.(as if they were greater than 1 the square of the other would be complex)
hence write l = cosx (for some x)
and m is the sin x
then divide al+bm=c by sqrta^2+b^2 (As a^2 + b^2 is not 0)
write the lhs as sin(j+x) (for some j)
hence as the sin function oscillates between -1 and 1
c oscillates between -sqrt a^2 + b^2 to sqrt a^2+b^2
i know i didnt write clearly but hope u get what im saying
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yea, i got to what you are trying to say......it's great and right.....a good job...then wait for tomorrow for an another great problem......keep in touch....:--]
The answer is a
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how got to answer.....?..... :-o
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It can be seen through this... most of the above portion ... an expression of the form {Asinx +(or -) Bcosx} oscillates between +(-) sqrt(a^2 + b^2) ...
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using cauchy-schwarz inequality,we have (a^2+b^2)(l^2+m^2)>=(al+bm)^2=c^2,which implies A
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good idea......you are then showing acumen over problem solving....great application...thanx.....