3 Resistance Wheatstone Bridge

Consider the Wheatstone Bridge circuit. If the resistances R1 and R2 were zero(i.e if they were not present without altering the connections) then, the ratio of resistances will be 0:0. Will the current passing through G still be zero?

Easy Math Editor

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Comments

If $R_1 = R_2 = 0 \Omega$ , then $CAD$ is a short. So, $R_k$ , $R_x$ , and $G$ are shorted out of the circuit.

This means that the currents through $R_k$ , $R_x$ , and $G$ are all $0 A$ .

Jimmy Kariznov - 7 years, 10 months ago

No current will pass through points CD, as the equivalent resistance between those points would be $R_{eq}=\frac{0[R_k+R_x]}{0+ R_k+R_x} = 0$ . And since resistance is zero, no current will flow through $CD$ .

Akshat Jain - 7 years, 10 months ago

zero A

Ahmed Elgazar - 7 years, 10 months ago

Saransh Upadhyaya - 6 years, 7 months ago

yes?

Mario Vale - 6 years, 1 month ago

YES

Swarali Patil - 6 years, 1 month ago

Math	Appears as
Remember to wrap math in `\(` ... `\)` or `\[` ... `\]` to ensure proper formatting.
`2 \times 3`	$2 \times 3$
`2^{34}`	$2^{34}$
`a_{i-1}`	$a_{i-1}$
`\frac{2}{3}`	$\frac{2}{3}$
`\sqrt{2}`	$\sqrt{2}$
`\sum_{i=1}^3`	$\sum_{i=1}^3$
`\sin \theta`	$\sin \theta$
`\boxed{123}`	$\boxed{123}$