A baffling geometry question

In the given figure, P and Q are point of contact. O is the incentre. Line BO produced, meets PQ at G. Find the value of angle AGB?

The reason i shared the question as a note is that i don't know the answer. Try it out, & if you solve, please post a rigorous solution rather than mere guess.

#Geometry #Trigonometry #TriangleProperties #Triangle #Incircle

Note by Sanjeet Raria
6 years, 9 months ago

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Comments

Check out this graphic

Baffling Geometry Baffling Geometry

With lots of angle-chasing, it can be worked out that, given angles a,ba, b, the following angles are

OAP=90ab\angle OAP=90-a-b
OGP=90+a+b\angle OGP=90+a+b
AOG=90a\angle AOG=90-a
APG=90+a\angle APG=90+a

Hence, APGOAPGO is a cyclic quadrilateral. Moreover, since APOAPO is a right triangle, AOAO is the diameter of the circle that circumscribes the cyclic quadrilateral APGOAPGO. Hence, AGOAGO is also a right triangle, and we have our answer.

Michael Mendrin - 6 years, 9 months ago

Here is another way to prove it. It is easy to see PQC=BAC/2+ABC/2 \angle PQC = {\angle BAC} /2 + {\angle ABC}/2 . So you can get BGQ=BAC/2=BAO \angle BGQ = {\angle BAC} /2 = \angle BAO, therefore BGQBAO \triangle BGQ \sim \triangle BAO and BG×BO=BQ×BA BG \times BO = BQ \times BA . Let the point of contact of incircle with AB is D, we have BG×BO=BD×BA BG \times BO = BD \times BA . So AGOD is cyclic. AGB=BDO=90 \angle AGB = \angle BDO = 90 ^ \circ

Roger Lu - 6 years, 9 months ago

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You haven't defined the point DD in this proof. But it is simply the point touching the circle on the segment ABAB.

mathh mathh - 6 years, 9 months ago

AP PG GB

Shanzkie Vargas - 6 years, 9 months ago

Construct a model diagram with AC and BC AB as tangents

führer sy - 6 years, 8 months ago

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With any dimensions of radius and lengths of triangle

führer sy - 6 years, 8 months ago

I took an equilateral triangle and using coordinate geometry found out the value of the angle. Is the method legitimate?

Kartik Raj - 6 years, 9 months ago

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You've only found it when the triangle is equilateral. You haven't proved that the angle is the same for all triangles. You can't assume that all the triangles have the same angle just because the question asks for a single unique numeric value.

mathh mathh - 6 years, 9 months ago

90

führer sy - 6 years, 8 months ago
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