A doubt of Integrals !

Find the value of the definite integral : 01(1+ex2)dx \displaystyle \int_0^1( 1+e^{-x^{2}} )dx

#Calculus

Note by Rishu Jaar
3 years, 7 months ago

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Comments

Read Error function.

Pi Han Goh - 3 years, 7 months ago

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@Pi Han Goh , thank you , its a jee 1981 question but didn't knew the maths involved was so higher.

Rishu Jaar - 3 years, 7 months ago

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Then you can only evaluate it using numerical methods, like trapezoidal rule or Simpson's rule.

Pi Han Goh - 3 years, 7 months ago

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@Pi Han Goh Thanks , could you provide a link?

Rishu Jaar - 3 years, 7 months ago

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@Rishu Jaar Trapezium Rule

Pi Han Goh - 3 years, 7 months ago

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@Pi Han Goh Thanks!

Rishu Jaar - 3 years, 7 months ago

@Rishabh Cool and others please give a proof !

Rishu Jaar - 3 years, 7 months ago

If, by value, you mean the area under the curve from 0 to 1, the solution would be 1/2 sqrt(π) • e • rf(1) + 1. This is simply found by removing the parentheses, taking the derivative, and then solving from there as usual.

Hunter Edwards - 3 years, 7 months ago

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Oh can you explain more.

Rishu Jaar - 3 years, 7 months ago

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Yes - I'll post a new discussion called JEE 1981 Int Calc with the information enclosed. I need my LaTeX!

Hunter Edwards - 3 years, 7 months ago

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@Hunter Edwards Ok sure.

Rishu Jaar - 3 years, 7 months ago

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@Rishu Jaar @RISHU Jaar It's in the new section.

Hunter Edwards - 3 years, 7 months ago

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@Hunter Edwards Done.

Rishu Jaar - 3 years, 7 months ago
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