A game of dice

You are given 3 dice as shown in the figure above where the numbers on the opposite faces of the each of the dice are equal.(For example,the number opposite to 6 in the first dice is also 6.)

Now the game begins like this I choose 1 dice and you choose another one from the remaining and after rolling whichever comes up with larger value wins the game.By choosing which dice are you more likely to win(that is with greater probability) in the following cases:

A.I choose dice A.

B.I choose dice B

C.I choose dice C

#Combinatorics #Probability #Goldbach'sConjurersGroup #TorqueGroup #IntroduceYourself

Note by Eddie The Head
7 years ago

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Comments

A beats B, B beats C, and C beats A, all with 5/9 probability. Nontransistive dice, i.e, A > B > C > A

Michael Mendrin - 7 years ago

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Haha....indeed....but rolling twice the case becomes entirely opposite.....but does a pattern hold if we generalize it to k rolls?

Eddie The Head - 7 years ago

I believe non-transitive dice were discovered, if not just made popular, by Dr. James Grime (seen on numberphile)?

Daniel Liu - 7 years ago

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Yeah...I remember seeing that on numberphile too....

Eddie The Head - 7 years ago

A. I will choose dice C B. I will choose dice A C. I will choose dice B

Venkii Rv - 7 years ago

Though withoutvan answer its a beautiful question

Muhsin Haneefa - 7 years ago

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If you want the answer you may choose to read on non-transitive dice

Eddie The Head - 7 years ago

A is actually no better than B, and B is no better than C. If u calculate the expected values, they are just the same. This means it will be a fair bet between any chosen pair of dice if u include the rewards for winning a bet as the difference in numbers rolled on the dice. When we choose A to bet with B, for instance, it is possible to get more rewards on B (example: u roll a 9) even when there is a lower probability (4/9) to win.

Cheah Chung Yin - 7 years ago

I choose c...c<a

Shrevarna Shaji - 7 years ago
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