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Sir, Can you please suggest me where can I learn about functions & solving these type of questions? Honestly, I don't know much about this topic , please help me, thank you.!
Easy Math Editor
This discussion board is a place to discuss our Daily Challenges and the math and science related to those challenges. Explanations are more than just a solution — they should explain the steps and thinking strategies that you used to obtain the solution. Comments should further the discussion of math and science.
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2^{34}
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Comments
I'll assume that the domain is R−{−cd}
If ab=cd, then the range is R−{ca} if c=0 and R otherwise.
If equality holds above, then f(x) is a constant function, which contradicts the fact that f(19)=f(97).
In conclusion, the range is R−{ca} if c=0 otherwise R.
Edit:
After finding a,b,c,d,
Either f(x)=x or f(x)=x−5858x−19×97
So, the range is either R or R−{58}
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So every x we put, the answer is always real ?
So how about f(0)?
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Oops, sorry for late reply. Whats the problem if we put f(0).
f(0)=c×0+da×0+b=db.
Since c−d is removed from its domain, the answer db is real too.
I don't know functions well , can you please explain a bit more on how you took the range?
The answer is R−58 since there is no x value for 58
Domain
x∈R:x=58
Range
f∈R:f=58
Check this out
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Sir, Can you please suggest me where can I learn about functions & solving these type of questions? Honestly, I don't know much about this topic , please help me, thank you.!
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Practice the challenge quizzes in the chapter and read the wikis.
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Wow, that guy really wrote the same problem. We both came from Indonesia :)
@Abhay Kumar @Ashish Siva @Margaret Zheng @Mark C @Rishabh Tiwari @Rishabh Cool @Pi Han Goh
Anyone ?
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why not me???
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Sorry, forgot u :(