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2 \times 3
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2^{34}
234
a_{i-1}
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\frac{2}{3}
32
\sqrt{2}
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Comments
We will try and get a Diophantine equation you can factor. Let x and y be the 2 shorter sides of the right angle triangle.
x+y+x2+y2=60
60−x−y=x2+y2
3600+x2+y2−120x−120y+2xy=x2+y2
xy−60x−60y+1800=0
(x−60)(y−60)=1800
We also have x,y<60 since the perimeter must be 60. So, both brackets must be negative. Also, x,y>0 since our triangle is non-degenerate. This implies that −60<x−60<0,−60<y−60<0. We can use this to remove certain factors of 1800.
Now we list all factors of 1800 which its complement that also satisfy the above ranges.
1800=(−36,−50),(−40,−45)
From this, we get (x,y) values of (24,10) and (20,15). Thus, the only triangles which satisfy are the 10-24-26 triangle and the 15-20-25 triangle.
Note: I didn't bother with solutions (10,24) and (15,20) since they gave the same triangles.
Easy Math Editor
This discussion board is a place to discuss our Daily Challenges and the math and science related to those challenges. Explanations are more than just a solution — they should explain the steps and thinking strategies that you used to obtain the solution. Comments should further the discussion of math and science.
When posting on Brilliant:
*italics*
or_italics_
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or__bold__
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[example link](https://brilliant.org)
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\(
...\)
or\[
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to ensure proper formatting.2 \times 3
2^{34}
a_{i-1}
\frac{2}{3}
\sqrt{2}
\sum_{i=1}^3
\sin \theta
\boxed{123}
Comments
We will try and get a Diophantine equation you can factor. Let x and y be the 2 shorter sides of the right angle triangle.
x+y+x2+y2=60
60−x−y=x2+y2
3600+x2+y2−120x−120y+2xy=x2+y2
xy−60x−60y+1800=0
(x−60)(y−60)=1800
We also have x,y<60 since the perimeter must be 60. So, both brackets must be negative. Also, x,y>0 since our triangle is non-degenerate. This implies that −60<x−60<0,−60<y−60<0. We can use this to remove certain factors of 1800.
Now we list all factors of 1800 which its complement that also satisfy the above ranges.
1800=(−36,−50),(−40,−45)
From this, we get (x,y) values of (24,10) and (20,15). Thus, the only triangles which satisfy are the 10-24-26 triangle and the 15-20-25 triangle.
Note: I didn't bother with solutions (10,24) and (15,20) since they gave the same triangles.