A problem on Floor and Ceiling Functions!

Is it true or false?

1+1+8n21=2n\large{\left \lceil \dfrac{1 + \sqrt{1+8n}}{2} \right \rceil - 1 = \left \lfloor \sqrt{2n} \right \rfloor}

Here nn is a positive integer.

If it is false, provide me a counter-example. If it's true, please provide me a proof.

#Algebra #GreatestIntegerFunction(Floor) #CeilingFunction #FloorFunction

Note by Satyajit Mohanty
5 years, 10 months ago

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Comments

False. Often, they don't agree.

Michael Mendrin - 5 years, 10 months ago

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I'm sorry. I forgot to mention that nn is a positive integer! Can you find some counter-example now?

Satyajit Mohanty - 5 years, 10 months ago

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..

12(1+1+84)1=2.37228...\dfrac { 1 }{ 2 } (1+\sqrt { 1+8\cdot 4 } )-1=2.37228...
24=2.828427...\sqrt { 2\cdot 4 } =2.828427...

But because of the way ceiling and floor functions work, these two go off in opposite directions. This is just one example.

Michael Mendrin - 5 years, 10 months ago

if n = 2 it is not true

the only solutions are: 0,1,3,4,6

John Doe - 5 years, 10 months ago

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It is true for n=2n=2. I don't agree!

Satyajit Mohanty - 5 years, 10 months ago

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[] means floor?

John Doe - 5 years, 10 months ago

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@John Doe Look. .\lceil . \rceil means ceiling and .\lfloor . \rfloor means floor.

Satyajit Mohanty - 5 years, 10 months ago

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@Satyajit Mohanty Ah- i see =)

John Doe - 5 years, 10 months ago

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@John Doe It's not true when n = 12 (calculated with Wolfram Alpha)

John Doe - 5 years, 10 months ago

@Satyajit Mohanty It's not true when n = 12 (calculated with Wolfram Alpha)

John Doe - 5 years, 10 months ago

Hint: Consider what happens when k22n<(k+1)2 k^2 \leq 2n < (k+1)^2 .

Calvin Lin Staff - 5 years, 10 months ago

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Thanks :) I got it. I actually had a doubt on a solution to this problem: Peculiar Sequence of Positive Integers! as the generalized version of my solution did not match the generalized version of the other solution.

Satyajit Mohanty - 5 years, 10 months ago

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If you see my note, I was pointing out the mistake that @Chew-Seong Cheong made in the generalization.

The true version of the statement that you are looking for, is

1+1+8n2=2n+32{\left \lceil \dfrac{1 + \sqrt{1+8n}}{2} \right \rceil = \left \lfloor \sqrt{2n} + \frac{3}{2} \right \rfloor}

Calvin Lin Staff - 5 years, 10 months ago
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